document.write( "Question 469069: the length of a rectagular mailing label is 4 centimeters less than twice the width. The perimeter is 52 centimeters. Find the dimensions of the label. \n" ); document.write( "

Algebra.Com's Answer #321855 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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Let x cm is the width of a rectagular mailing label
\n" ); document.write( "The length of a rectagular mailing label is 4 centimeters less than twice the width, then the length is $\"2x-4\"$ cm
\n" ); document.write( "The perimeter of a rectangle is $\"P=2%28l%2Bw%29\"$ , where l is the length, w is the width
\n" ); document.write( "Equation $\"2%28x%2B2x-4%29=52\"$ divide by 2
\n" ); document.write( " $\"3x-4=26\"$
\n" ); document.write( " $\"3x=26%2B4\"$
\n" ); document.write( " $\"3x=30\"$
\n" ); document.write( " $\"x=30%2F3\"$
\n" ); document.write( " $\"x=10\"$ cm is the width of a rectagular mailing label
\n" ); document.write( "The length is $\"2%2A10-4=16\"$ cm \n" ); document.write( "

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