document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469086>Question 469086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a sum of 20000 is invested, part at 10% and the remainder at 8%, find the amount invested at in each rate if the yearly income to the two investments is 1840 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321854 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+y=20000	------------------------1				<BR>\n" );
document.write( "10.00%	x+8.00%	y	=	$1,840.00			<BR>\n" );
document.write( "Multiply by 	100							<BR>\n" );
document.write( "10x+8y=	$184,000.00		--------2	<BR>\n" );
document.write( "									<BR>\n" );
document.write( "Multiply (1) by	-10						<BR>\n" );
document.write( "we get									<BR>\n" );
document.write( "									<BR>\n" );
document.write( "-10x-10	y=-200000.00			<BR>\n" );
document.write( "									<BR>\n" );
document.write( "Add this to (2)									<BR>\n" );
document.write( "									<BR>\n" );
document.write( "-2y=-$16,000.00			<BR>\n" );
document.write( "									<BR>\n" );
document.write( "divide by		-2							<BR>\n" );
document.write( "									<BR>\n" );
document.write( "y	=		$8,000.00	investment at 	8.00%<BR>\n" );
document.write( "Balance			$12,000.00	investment at 	10.00%<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );