document.write( "Question 469091: Elaan paddled out to check on her crab traps. Going to the traps she caught a falling tide, that increased her normal speed by 2mph. but coming back it decreased her speed by 2 mph. Going with the tide , the trip took only 10 min. The return, against the tide, took 20 min. How far out are the traps from the shore?\r
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document.write( "I've tried to set up the chart and declare the variables but I've only seen current problems where the the unknown is the speed of the current/boat. I don't know how to set up the system to find the distance. Help Please =) Thank you for your time. \n" );
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Algebra.Com's Answer #321847 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let boat speed = x \n" ); document.write( "with current = x+2 mph ----- time = 10 minutes \n" ); document.write( "against current = x-2 mph----time = 20 minutes\r \n" ); document.write( "\n" ); document.write( "Distance = same both ways\r \n" ); document.write( "\n" ); document.write( "r*t = distance\r \n" ); document.write( "\n" ); document.write( "1/6(x+2)= 1/3(x-2)\r \n" ); document.write( "\n" ); document.write( "3(x+2)=6(x-2)\r \n" ); document.write( "\n" ); document.write( "3x+6=6x-12 \n" ); document.write( "6x-3x=18 \n" ); document.write( "3x=18 \n" ); document.write( "x=6\r \n" ); document.write( "\n" ); document.write( "D= rt \n" ); document.write( "D= 1/6 *8= 4/3 miles\r \n" ); document.write( "\n" ); document.write( "D=rt \n" ); document.write( "D= 1/3*4= 4/3 miles\r \n" ); document.write( "\n" ); document.write( "Distance was 4/3 miles\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |