document.write( "Question 469112: if a rectangle has a diagonal of 40 inches what is the height and width if the width is 8 inches longer than the height? \n" ); document.write( "
Algebra.Com's Answer #321846 by Tatiana_Stebko(1539)\"\" \"About 
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Let x is the height of a rectangle
\n" ); document.write( "If the width is 8 inches longer than the height, then the width is \"%28x%2B8%29\" inches
\n" ); document.write( "Use the Pythagorean theorem
\n" ); document.write( "\"x%5E2%2B%28x%2B8%29%5E2=40%5E2\"
\n" ); document.write( "\"x%5E2%2Bx%5E2%2B16x%2B64-1600=0\"
\n" ); document.write( "\"2x%5E2%2B16x-1536=0\" divide by 2
\n" ); document.write( "\"x%5E2%2B8x-768=0\"
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%28-8+%2B-+sqrt%288%5E2-4%2A1%2A%28-768%29+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"x+=+%28-8+%2B-+sqrt%283136%29%29%2F2+\"
\n" ); document.write( "\"x+=+%28-8+%2B56%29%2F2=24+\" inches is the height of a rectangle
\n" ); document.write( "\"x+=+%28-8+-56%29%2F2=-32%3C0+\" the extraneous root
\n" ); document.write( "The height of a rectangle is 24 inches, the width is 24+8=32 inches
\n" ); document.write( "Answer: 24 inches, 32 inches
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