document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469094>Question 469094</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perez paddles 55m per minute in still water.  If he paddles 135m upstream in 3 minutes, what is the speed of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321836 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321836\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d,r,t be distance, rate and time<BR>\n" );
document.write( "Let c be rate of current<BR>\n" );
document.write( "d = r*t<BR>\n" );
document.write( "d = 135<BR>\n" );
document.write( "r = 55-c (since its upstream, current slows him down)<BR>\n" );
document.write( "t = 3<BR>\n" );
document.write( "=> 135 = 3(55-c)<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "135 = 165 - 3c<BR>\n" );
document.write( "Add 3c to both sides, Subtract 135 to both sides<BR>\n" );
document.write( "3c = 30<BR>\n" );
document.write( "Divide by 3 on both sides<BR>\n" );
document.write( "c = 10<BR>\n" );
document.write( "The speed of the current is 10 meters per min </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );