document.write( "Question 469053: pure acid is to be added to a 10% acid solution to obtain 90L of 19% solution. what amounts of each should be added? \n" ); document.write( "
Algebra.Com's Answer #321817 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! n+.1(90-n)=90(.19) \n" ); document.write( "n+9-.1n=17.1 \n" ); document.write( ".9n=8.1 \n" ); document.write( "n=8.1/.9=9 \n" ); document.write( "9L of pure acid should be mixed with 81L of 10% acid for your mix.. \n" ); document.write( " |