document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48534>Question 48534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1/8 - 3/5 = 1/x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32179 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32179\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/8 - 3/5 = 1/x [Find the Least Common Denominator (LCD)]<BR>\n" );
document.write( "1/8 - 3/5 = 1/x}  [LCD = 8*5*x = 40x]<BR>\n" );
document.write( "(40x)(1/8) - (40x)(3/5) = (40x)(1/x) [Multiply each term by the LCD] <BR>\n" );
document.write( "5x - (8x)(3) = (40)  [Cancel out wherever possible]<BR>\n" );
document.write( "5x-24x=40 [Simplify]<BR>\n" );
document.write( "-19x=40<BR>\n" );
document.write( "x=-40/19<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Check by plugging (x=-40/19) back into the original equation and solve]<BR>\n" );
document.write( "1/8 - 3/5 = 1/(-40/19)<BR>\n" );
document.write( "-.475 = -.475 </SPAN>\n" );
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