document.write( "Question 468959: a motor boat travelling at 18 miles per hour travellled the length of a lake in one quarterof an hour less time than it took when travelling at 12 miles per hour. what was the length in miles of the lake? \n" ); document.write( "
Algebra.Com's Answer #321746 by ccs2011(207)\"\" \"About 
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Let d=distance, r=speed, t =time
\n" ); document.write( "d = r*t
\n" ); document.write( "******************
\n" ); document.write( "Trip 1:
\n" ); document.write( "t represents time to travel lake at 12 mph
\n" ); document.write( "\"d+=+18%28t-%281%2F4%29%29\"
\n" ); document.write( "Goal is to solve for d, so get t in terms of d
\n" ); document.write( "\"d%2F18+=+t+-+%281%2F4%29\"
\n" ); document.write( "\"%28d%2F18%29%2B%281%2F4%29+=+t\"
\n" ); document.write( "********************
\n" ); document.write( "Trip 2:
\n" ); document.write( "\"d+=+12t\"
\n" ); document.write( "\"d%2F12+=+t\"
\n" ); document.write( "*********************
\n" ); document.write( "Set equations equal to each other, since both are equal to t
\n" ); document.write( "\"d%2F12+=+%28d%2F18%29%2B%281%2F4%29\"
\n" ); document.write( "Eliminate fractions by multiplying equation by 36
\n" ); document.write( "LCM of 4,12,18 is 36 --> 4*9=36, 12*3 = 36, 18*2 =36
\n" ); document.write( "\"3d+=+2d+%2B+9\"
\n" ); document.write( "Subtract 2d on both sides
\n" ); document.write( "\"d+=+9\"
\n" ); document.write( "Length of lake is 9 mi.
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