document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468935>Question 468935</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 1993, there were 80 turtles living in a wetland. That year, the population began to grow by 12 turtles/year. Find a formula for P, the number of turtles, in terms of t, the number of years since 1993. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321715 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In 1993, there were 80 turtles living in a wetland. That year, the population began to grow by 12 turtles/year. Find a formula for P, the number of turtles, in terms of t, the number of years since 1993.<BR>\n" );
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document.write( "Develop a chart till you see the pattern:<BR>\n" );
document.write( "0-------80<BR>\n" );
document.write( "1-------80+12<BR>\n" );
document.write( "2-------80+2*12<BR>\n" );
document.write( "3-------80+3*12<BR>\n" );
document.write( "t-------80+12t<BR>\n" );
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document.write( "P = 12t+80 where t is the # of years after 1993<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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