document.write( "Question 468796: During the first part of a trip a canoeist travels 45 miles at a certain speed. The canoeist travels 12 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 4 hrs. What was the total time on each trip? \n" ); document.write( "
Algebra.Com's Answer #321693 by ankor@dixie-net.com(22740)\"\" \"About 
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During the first part of a trip a canoeist travels 45 miles at a certain speed.
\n" ); document.write( " The canoeist travels 12 miles on the second part of the trip at a speed 5 mph slower.
\n" ); document.write( "The total time for the trip is 4 hrs.
\n" ); document.write( " What was the total time on each trip?
\n" ); document.write( ":
\n" ); document.write( "Let s = speed for the 1st 45 mi
\n" ); document.write( "then
\n" ); document.write( "(s-5) = speed for the last 12 mi
\n" ); document.write( ":
\n" ); document.write( "Write a time equation, time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "1st part time + 2nd part time = 4 hr
\n" ); document.write( "\"45%2Fs\" + \"12%2F%28%28s-5%29%29\" = 4
\n" ); document.write( "multiply by s(s-5), results:
\n" ); document.write( "45(s-5) + 12s = 4s(s-5)
\n" ); document.write( ":
\n" ); document.write( "45s - 225 + 12s = 4s^2 - 20s
\n" ); document.write( "57s - 225 = 4s^2 - 20s
\n" ); document.write( "Arrange as a quadratic on the right
\n" ); document.write( "0 = 4s^2 - 20s - 57s + 225
\n" ); document.write( ":
\n" ); document.write( "4s^2 - 77s + 225 = 0
\n" ); document.write( "Solve this with the quadratic formula,
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this problem we have:
\n" ); document.write( "\"s+=+%28-%28-77%29+%2B-+sqrt%28-77%5E2-4%2A4%2A225+%29%29%2F%282%2A4%29+\"
\n" ); document.write( "Do the math, only one solution will make sense
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