document.write( "Question 468796: During the first part of a trip a canoeist travels 45 miles at a certain speed. The canoeist travels 12 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 4 hrs. What was the total time on each trip? \n" ); document.write( "
Algebra.Com's Answer #321693 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! During the first part of a trip a canoeist travels 45 miles at a certain speed. \n" ); document.write( " The canoeist travels 12 miles on the second part of the trip at a speed 5 mph slower. \n" ); document.write( "The total time for the trip is 4 hrs. \n" ); document.write( " What was the total time on each trip? \n" ); document.write( ": \n" ); document.write( "Let s = speed for the 1st 45 mi \n" ); document.write( "then \n" ); document.write( "(s-5) = speed for the last 12 mi \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "1st part time + 2nd part time = 4 hr \n" ); document.write( " \n" ); document.write( "multiply by s(s-5), results: \n" ); document.write( "45(s-5) + 12s = 4s(s-5) \n" ); document.write( ": \n" ); document.write( "45s - 225 + 12s = 4s^2 - 20s \n" ); document.write( "57s - 225 = 4s^2 - 20s \n" ); document.write( "Arrange as a quadratic on the right \n" ); document.write( "0 = 4s^2 - 20s - 57s + 225 \n" ); document.write( ": \n" ); document.write( "4s^2 - 77s + 225 = 0 \n" ); document.write( "Solve this with the quadratic formula, \n" ); document.write( " \n" ); document.write( "In this problem we have: \n" ); document.write( " \n" ); document.write( "Do the math, only one solution will make sense \n" ); document.write( " \n" ); document.write( " |