document.write( "Question 468855: Two investments are made totaling $8800. For a certain year, these investments yield $1326 in simple interest. Part of the $8800 is invested at 16% and part at 14%. Find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #321674 by mananth(16946)![]() ![]() You can put this solution on YOUR website! x + y 8800 ------------------------1 \n" ); document.write( "14.00% x + 16.00% y = $1,326.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "14 x + 16 y = $132,600.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -14 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-14 x -14 y = -123200.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "0 x 2 y = $9,400.00 \n" ); document.write( " \n" ); document.write( "divide by 2 \n" ); document.write( " \n" ); document.write( "y =$4,700.00 investment at 16.00% \n" ); document.write( "Balance $4,100.00 investment at 14.00% \n" ); document.write( " \n" ); document.write( " |