document.write( "Question 468855: Two investments are made totaling $8800. For a certain year, these investments yield $1326 in simple interest. Part of the $8800 is invested at 16% and part at 14%. Find the amount invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #321674 by mananth(16946)\"\" \"About 
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x + y 8800 ------------------------1
\n" ); document.write( "14.00% x + 16.00% y = $1,326.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "14 x + 16 y = $132,600.00 --------2
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\n" ); document.write( "Multiply (1) by -14
\n" ); document.write( "we get
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\n" ); document.write( "-14 x -14 y = -123200.00
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "0 x 2 y = $9,400.00
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\n" ); document.write( "divide by 2
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\n" ); document.write( "y =$4,700.00 investment at 16.00%
\n" ); document.write( "Balance $4,100.00 investment at 14.00%
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