document.write( "Question 468836: An artillery observer in an airplane agrees that when he gets above a target which is invisible from the guns he will level off at 10,000 feet elevation. If at that instant his angle of elevation as seen from the guns is 28degrees 20minutes, find the distance from the guns to the target. \n" ); document.write( "

Algebra.Com's Answer #321663 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
10000/tan(28.333) = distance in feet
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