document.write( "Question 468755: Hi! I need help with two problems please? The only thing I am understanding is the minimum and maximum values. I cannot get the figures right.
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document.write( "Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function.
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document.write( "f(x)=-2x^2+2x+4
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document.write( "f(x)= 1-x^2 \n" );
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Algebra.Com's Answer #321633 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the vertex, the line of symmetry, the maximum or minimum value of the quadratic function and graph the function. \n" ); document.write( "f(x)=-2x^2+2x+4 \n" ); document.write( "f(x)= 1-x^2 \n" ); document.write( "... \n" ); document.write( "Standard form of parabola: y=ħA(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( "If the lead coefficient is>0, the parabola opens upwards and there is a minimum. If the lead coefficient is <0, the parabola opens downwards and there is a maximum. A is a multiplier which affects the steepness of the parabola. \n" ); document.write( ".. \n" ); document.write( "f(x)=-2x^2+2x+4 \n" ); document.write( "completing the square \n" ); document.write( "f(x)=-2(x^2-x+1/4)+4+1/2 \n" ); document.write( "f(x)=-2(x-1/2)^2+9/2 \n" ); document.write( "This is a parabola which opens downwards with vertex at (1/2,9/2). (maximum=9/2) \n" ); document.write( "Axis of symmetry: x=1/2 \n" ); document.write( ".. \n" ); document.write( "f(x)= 1-x^2 \n" ); document.write( "f(x)=-x^2+1 \n" ); document.write( "Already in standard form,This is a parabola which opens downwards with vertex at (0,1). (maximum=1) \n" ); document.write( "Axis of symmetry: x=0 or y-axis \n" ); document.write( "See graph below as a visual check on answers \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( " |