document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468759>Question 468759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This question is about Factoring the sum and difference of two cubes.<BR>\n" );
document.write( "8a(cube)- 64 = </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321620 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321620\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 8a³ - 64\r<BR>\n" );
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document.write( "It is a difference of two cubes in the form a³ - b³,<BR>\n" );
document.write( "it factors into the form (a - b)(a² + ab + b²)\r<BR>\n" );
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document.write( "If a³ is 8a³, then a is 2a {the cube root of 8a³}<BR>\n" );
document.write( "If b³ is 64, then b is 4 {the cube root of 64}\r<BR>\n" );
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document.write( "8a³ - 64<BR>\n" );
document.write( "= (2a - 4)(4a² + 8a + 16) {substituted 2a, in for a, and 4, in for b, into (a - b)(a² + ab + b²)}<BR>\n" );
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