document.write( "Question 468719: Given \"f%28x%29+=+sqrt%282x-3%29\", find f(12.8) Your answer should be written in decimal notation, rounded to 4 decimal places. \n" ); document.write( "
Algebra.Com's Answer #321588 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+sqrt%282x-3%29\", find \"f%2812.8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%2812.8%29+=+sqrt%282%2812.8%29-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%2812.8%29+=+sqrt%2825.6-3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%2812.8%29+=+sqrt%2822.6%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%2812.8%29+=+4.7539457296018851376161486551456\"\r
\n" ); document.write( "\n" ); document.write( "\"f%2812.8%29+=+4.7539\"
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