document.write( "Question 468615: 5. Solve the following equation in the real number system. Please show all of your work.
\n" ); document.write( " x³-6x²-10x+12=0
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Algebra.Com's Answer #321576 by lwsshak3(11628)\"\" \"About 
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5. Solve the following equation in the real number system. Please show all of your work.
\n" ); document.write( "x³-6x²-10x+12=0
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\n" ); document.write( "f(x)=x³-6x²-10x+12
\n" ); document.write( "A graphing calculator will show that there is one zero at x=-2
\n" ); document.write( "Divide f(x) by (x+2) by long division or synthetic division
\n" ); document.write( "(x³-6x²-10x+12)/(x+2)=x^2-8x+6
\n" ); document.write( "solve for other two zeros
\n" ); document.write( "x^2-8x+6=0
\n" ); document.write( "complete the square
\n" ); document.write( "(x^2-8x+16)+6-16=0
\n" ); document.write( "(x-4)^2=10
\n" ); document.write( "x-4=±√10
\n" ); document.write( "x=4±√10=7.16 and -.84
\n" ); document.write( "ans:
\n" ); document.write( "x=-2, -.84 and 7.16
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