document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48573>Question 48573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solution x is 2% alcohol and solution y is 6% alcohol. A drugstore owner wants to mix them in order to get a 60 liter of solution that is 3.2% alcohol. How many liters of each should the owner use?\r<BR>\n" );
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document.write( "My dear tutor i would be very glad if you can help me solved this problem. I had been trying my very best but really iam poor in math. THANKS so much and more power........ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32157 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> DEFINITION:<BR>\n" );
document.write( "Let x = amount of solution needed.<BR>\n" );
document.write( "Leap of common sense... how much of solution y is therefore needed? Answer is \"the rest of the 60litres\", so we have (60-x).\r<BR>\n" );
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document.write( "BEFORE:<BR>\n" );
document.write( "0.02*x + 0.06(60-x)\r<BR>\n" );
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document.write( "AFTER:<BR>\n" );
document.write( "0.32*60\r<BR>\n" );
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document.write( "and the before must equal the after surely? :-) so...<BR>\n" );
document.write( "0.02*x + 0.06(60-x) = 0.032*60<BR>\n" );
document.write( "0.02x + 3.6-0.06x = 1.92<BR>\n" );
document.write( "-0.04x = -1.68<BR>\n" );
document.write( "x = (-1.68)/(-0.04)<BR>\n" );
document.write( "x = 42 litres.\r<BR>\n" );
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document.write( "And so 60-42 is 18.\r<BR>\n" );
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document.write( "x=42litres<BR>\n" );
document.write( "y=18 litres\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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