document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468511>Question 468511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 13/12 is the arithemetic mean is a & b, and a is recipocal of b.then find a & b.     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321516 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321516\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 13/12 is the arithemetic mean is a & b, and a is recipocal of b.then find a & b.\r<BR>\n" );
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document.write( "Solution,\r<BR>\n" );
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document.write( "13/12 is the arithemetic mean is a & b<BR>\n" );
document.write( " (a + b)/2 = 13/12<BR>\n" );
document.write( "  a + b = 13/6 ----(1)\r<BR>\n" );
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document.write( "a is recipocal of b<BR>\n" );
document.write( " a = 1/b ----(2)\r<BR>\n" );
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document.write( "substitute (2) into (1)\r<BR>\n" );
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document.write( " [(1/b) + b = 13/6] x 6b<BR>\n" );
document.write( " 6 + 6b^2 = 13b<BR>\n" );
document.write( " 6b^2 - 13b + 6 = 0<BR>\n" );
document.write( " (2b-3)(3b-2) = 0<BR>\n" );
document.write( " b = 3/2 and 2/3\r<BR>\n" );
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document.write( "when b = 3/2, a = 2/3 <---answer<BR>\n" );
document.write( "when b = 2/3, a = 3/2 <---answer\r<BR>\n" );
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