document.write( "Question 468526: i have tried to solve this log2(8-6x)=5. i cant seem to figure out what i am doing wrong. i have tried this: 2^5=8-6x. and so i add 8 to both sides and i get 40=6x then i divide both sides by 6 and i 6.666666? please help... thankyou \n" ); document.write( "
Algebra.Com's Answer #321493 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
\"log%282%2C%288-6x%29%29=5\"
\n" ); document.write( "\"8-6x=2%5E5\"
\n" ); document.write( "Subtract 8 from both sides of the equation
\n" ); document.write( "\"-6x=32-8\"
\n" ); document.write( "\"-6x=24\"
\n" ); document.write( "Divide both sides by -6
\n" ); document.write( "\"x=-24%2F6\"
\n" ); document.write( "\"x=-4\"
\n" ); document.write( "
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