document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468533>Question 468533</A>: <I><SPAN STYLE=\"word-break: break-all;\">  If 1/3 of an integer is added to 1/4 of the next consecutive integer the sum is 23. Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321481 by </B><A HREF=/tutors/aboutme.mpl?userid=asuar010><B>asuar010(338)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asuar010><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=asuar010><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simple.. denote the first integer to be x, then the next integer is (x+1)\r<BR>\n" );
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document.write( "Now just rewrite the problem using numbers... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281%2F3%29%2Ax+%2B+%281%2F4%29%2A%28x%2B1%29=23+ ALIGN=MIDDLE  ALT=\"+%281%2F3%29%2Ax+%2B+%281%2F4%29%2A%28x%2B1%29=23+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "to get rid of the fractions multiply the whole equation by 12 and it should look like:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4x%2B3x%2B3=276+ ALIGN=MIDDLE  ALT=\"+4x%2B3x%2B3=276+\"   DISABLED_style= \"max-width:90%; height:auto;\" > then solve for x. <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+7x=273+ ALIGN=MIDDLE  ALT=\"+7x=273+\"   DISABLED_style= \"max-width:90%; height:auto;\" > so x=39\r<BR>\n" );
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document.write( "So the numbers are 39 and 40...\r<BR>\n" );
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document.write( "To check if you add 39/3+40/4=23 </SPAN>\n" );
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