document.write( "Question 468367: Hi I was hoping someone could Please help me with this problem! Thank you so much!! :) \r
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\n" ); document.write( "\n" ); document.write( "Movies A survey of 350 customers was taken at Regal Cinemas in Austin, Texas, regarding the type of movies customers liked. The following information was determined.
\n" ); document.write( " 196 liked dramas.153 liked comedies.
\n" ); document.write( " 88 liked science fiction.
\n" ); document.write( " 59 liked dramas and comedies.
\n" ); document.write( " 37 liked dramas and science fiction.
\n" ); document.write( " 32 liked comedies and science fiction.
\n" ); document.write( " 21 liked all three types of movies. \r
\n" ); document.write( "\n" ); document.write( "Of the customers surveyed, how many liked
\n" ); document.write( " a)none of these types of movies?
\n" ); document.write( " b)only dramas?
\n" ); document.write( " c)exactly one of these types of movies?
\n" ); document.write( " d)exactly two of these types of movies?
\n" ); document.write( " e)dramas or comedies?
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Algebra.Com's Answer #321433 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
The general formula for the union of 3 sets is:
\n" ); document.write( "(A union B union C) = A + B + C - (A intersect B) - (A intersect C) - (B intersect C) + (A intersect B intersect C).
\n" ); document.write( "We will assign the following:
\n" ); document.write( "A = drama
\n" ); document.write( "B = comedy
\n" ); document.write( "C = science
\n" ); document.write( "A intersect B = drama + comedy = AB
\n" ); document.write( "A intersect C = drama + science = AC
\n" ); document.write( "B intersect C = comedy + science = BC
\n" ); document.write( "A intersect B intersect C = dramw + comedy + science (all 3) = ABC
\n" ); document.write( "We will now assign numbers to each of these sets:
\n" ); document.write( "A = 196
\n" ); document.write( "B = 153
\n" ); document.write( "C = 88
\n" ); document.write( "AB = 59
\n" ); document.write( "AC = 37
\n" ); document.write( "BC = 32
\n" ); document.write( "ABC = 21
\n" ); document.write( "We plug these numbers into the formula and we get:
\n" ); document.write( "A union B union C = 196 + 153 + 88 - 59 - 37 - 32 + 21
\n" ); document.write( "This becomes:
\n" ); document.write( "A union B union C = 330
\n" ); document.write( "Since there are 350 customers who were surveyed, that leaves 20 who did not like any of the selections.
\n" ); document.write( "We need to separate out the categories a little better in order to answer the rest of the questions.
\n" ); document.write( "We'll start with ABC.
\n" ); document.write( "There are 21 in that category.
\n" ); document.write( "We'll then move up to AB, AC, and BC.
\n" ); document.write( "Those categories each include ABC so we'll need to remove them from each of those categories.
\n" ); document.write( "AB = 59 - 21 = 38 that are in AB only.
\n" ); document.write( "AC = 37 - 21 = 16 that are in AC only.
\n" ); document.write( "BC = 32 - 21 = 11 that are in BC only.
\n" ); document.write( "We'll then move up to A, B, and C.
\n" ); document.write( "Those categories each include AB, AC, BC, and ABC.
\n" ); document.write( "We'll need to remove them to get A only, B only, C only.
\n" ); document.write( "We need to remove AB, AC, and ABC from A to get:
\n" ); document.write( "A DISABLED_event_only= 196 - 38 - 16 - 21 = 121.
\n" ); document.write( "We need to remove AB, BC, and ABC from B to get:
\n" ); document.write( "B DISABLED_event_only= 153 - 38 - 11 - 21 = 83
\n" ); document.write( "We need to remove AC, BC, and ABC from C to get:
\n" ); document.write( "C DISABLED_event_only= 88 - 16 - 11 - 21 = 40
\n" ); document.write( "We have now separated all these groups so there is no double counting in any of the groups.
\n" ); document.write( "We have:
\n" ); document.write( "A DISABLED_event_only= 121
\n" ); document.write( "B DISABLED_event_only= 83
\n" ); document.write( "C DISABLED_event_only= 40
\n" ); document.write( "A intersect B DISABLED_event_only= 38
\n" ); document.write( "A intersect C DISABLED_event_only= 16
\n" ); document.write( "B intersect C DISABLED_event_only= 11
\n" ); document.write( "A intersect B intersect C = 21
\n" ); document.write( "NOT (A union B union C) = 20 (don't like any of the 3 selections).
\n" ); document.write( "We add these all up and we get a total of 350 customers.
\n" ); document.write( "A Venn Diagram of these sets is shown below:
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\n" ); document.write( "There are a total of 330 customer in this Venn Diagram.
\n" ); document.write( "The 20 customer who did not have a preference are not shown.
\n" ); document.write( "This checks out with what we were told up front, so we probably did it right.
\n" ); document.write( "In removing the double counting, you have to work from the bottom layer up.
\n" ); document.write( "The bottom layer was A intersect B intersect C
\n" ); document.write( "The next bottom layer was A intersect B, A intersect C, B intersect C.
\n" ); document.write( "The top layer was A, B, and C
\n" ); document.write( "The higher layers include elements in the lower layers.
\n" ); document.write( "A intersect B intersect C was the lowest layer because it didn't include any sets that were part of it.
\n" ); document.write( "A intersect B, A intersect C, B intersect C were above ABC because they included ABC as part of their sets.
\n" ); document.write( "etc.
\n" ); document.write( "Your questions should be able to be answered now.
\n" ); document.write( "Those questions are:
\n" ); document.write( "a)none of these types of movies?
\n" ); document.write( "20
\n" ); document.write( "b)only dramas?
\n" ); document.write( "121
\n" ); document.write( "c)exactly one of these types of movies?
\n" ); document.write( "This would be A only plus B only plus C DISABLED_event_only= 121 + 83 + 40 = 244
\n" ); document.write( "d)exactly two of these types of movies?
\n" ); document.write( "This would be AB only + AC only + BC DISABLED_event_only= 65
\n" ); document.write( "e)dramas or comedies?
\n" ); document.write( "This would be A only + B only + AB only + AC only + BC only + ABC = 121 + 83 + 38 + 16 + 11 + 21 = 290.
\n" ); document.write( "It includes A only because they like drama.
\n" ); document.write( "It include B only because they like comedy.
\n" ); document.write( "It includes AB only because they like drama and comedy.
\n" ); document.write( "It includes AC only because they like drama.
\n" ); document.write( "It include BC only because they like comedy
\n" ); document.write( "It includes ABC only because they like drama and comedy.
\n" ); document.write( "The only category it does not include is C only. Those customers only like Science.
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