document.write( "Question 468367: Hi I was hoping someone could Please help me with this problem! Thank you so much!! :) \r
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document.write( "Movies A survey of 350 customers was taken at Regal Cinemas in Austin, Texas, regarding the type of movies customers liked. The following information was determined.
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document.write( " 196 liked dramas.153 liked comedies.
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document.write( " 88 liked science fiction.
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document.write( " 59 liked dramas and comedies.
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document.write( " 37 liked dramas and science fiction.
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document.write( " 32 liked comedies and science fiction.
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document.write( " 21 liked all three types of movies. \r
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document.write( "Of the customers surveyed, how many liked
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document.write( " a)none of these types of movies?
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document.write( " b)only dramas?
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document.write( " c)exactly one of these types of movies?
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document.write( " d)exactly two of these types of movies?
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document.write( " e)dramas or comedies? \n" );
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Algebra.Com's Answer #321433 by Theo(13342)![]() ![]() You can put this solution on YOUR website! The general formula for the union of 3 sets is: \n" ); document.write( "(A union B union C) = A + B + C - (A intersect B) - (A intersect C) - (B intersect C) + (A intersect B intersect C). \n" ); document.write( "We will assign the following: \n" ); document.write( "A = drama \n" ); document.write( "B = comedy \n" ); document.write( "C = science \n" ); document.write( "A intersect B = drama + comedy = AB \n" ); document.write( "A intersect C = drama + science = AC \n" ); document.write( "B intersect C = comedy + science = BC \n" ); document.write( "A intersect B intersect C = dramw + comedy + science (all 3) = ABC \n" ); document.write( "We will now assign numbers to each of these sets: \n" ); document.write( "A = 196 \n" ); document.write( "B = 153 \n" ); document.write( "C = 88 \n" ); document.write( "AB = 59 \n" ); document.write( "AC = 37 \n" ); document.write( "BC = 32 \n" ); document.write( "ABC = 21 \n" ); document.write( "We plug these numbers into the formula and we get: \n" ); document.write( "A union B union C = 196 + 153 + 88 - 59 - 37 - 32 + 21 \n" ); document.write( "This becomes: \n" ); document.write( "A union B union C = 330 \n" ); document.write( "Since there are 350 customers who were surveyed, that leaves 20 who did not like any of the selections. \n" ); document.write( "We need to separate out the categories a little better in order to answer the rest of the questions. \n" ); document.write( "We'll start with ABC. \n" ); document.write( "There are 21 in that category. \n" ); document.write( "We'll then move up to AB, AC, and BC. \n" ); document.write( "Those categories each include ABC so we'll need to remove them from each of those categories. \n" ); document.write( "AB = 59 - 21 = 38 that are in AB only. \n" ); document.write( "AC = 37 - 21 = 16 that are in AC only. \n" ); document.write( "BC = 32 - 21 = 11 that are in BC only. \n" ); document.write( "We'll then move up to A, B, and C. \n" ); document.write( "Those categories each include AB, AC, BC, and ABC. \n" ); document.write( "We'll need to remove them to get A only, B only, C only. \n" ); document.write( "We need to remove AB, AC, and ABC from A to get: \n" ); document.write( "A DISABLED_event_only= 196 - 38 - 16 - 21 = 121. \n" ); document.write( "We need to remove AB, BC, and ABC from B to get: \n" ); document.write( "B DISABLED_event_only= 153 - 38 - 11 - 21 = 83 \n" ); document.write( "We need to remove AC, BC, and ABC from C to get: \n" ); document.write( "C DISABLED_event_only= 88 - 16 - 11 - 21 = 40 \n" ); document.write( "We have now separated all these groups so there is no double counting in any of the groups. \n" ); document.write( "We have: \n" ); document.write( "A DISABLED_event_only= 121 \n" ); document.write( "B DISABLED_event_only= 83 \n" ); document.write( "C DISABLED_event_only= 40 \n" ); document.write( "A intersect B DISABLED_event_only= 38 \n" ); document.write( "A intersect C DISABLED_event_only= 16 \n" ); document.write( "B intersect C DISABLED_event_only= 11 \n" ); document.write( "A intersect B intersect C = 21 \n" ); document.write( "NOT (A union B union C) = 20 (don't like any of the 3 selections). \n" ); document.write( "We add these all up and we get a total of 350 customers. \n" ); document.write( "A Venn Diagram of these sets is shown below: \n" ); document.write( " ![]() \n" ); document.write( "There are a total of 330 customer in this Venn Diagram. \n" ); document.write( "The 20 customer who did not have a preference are not shown. \n" ); document.write( "This checks out with what we were told up front, so we probably did it right. \n" ); document.write( "In removing the double counting, you have to work from the bottom layer up. \n" ); document.write( "The bottom layer was A intersect B intersect C \n" ); document.write( "The next bottom layer was A intersect B, A intersect C, B intersect C. \n" ); document.write( "The top layer was A, B, and C \n" ); document.write( "The higher layers include elements in the lower layers. \n" ); document.write( "A intersect B intersect C was the lowest layer because it didn't include any sets that were part of it. \n" ); document.write( "A intersect B, A intersect C, B intersect C were above ABC because they included ABC as part of their sets. \n" ); document.write( "etc. \n" ); document.write( "Your questions should be able to be answered now. \n" ); document.write( "Those questions are: \n" ); document.write( "a)none of these types of movies? \n" ); document.write( "20 \n" ); document.write( "b)only dramas? \n" ); document.write( "121 \n" ); document.write( "c)exactly one of these types of movies? \n" ); document.write( "This would be A only plus B only plus C DISABLED_event_only= 121 + 83 + 40 = 244 \n" ); document.write( "d)exactly two of these types of movies? \n" ); document.write( "This would be AB only + AC only + BC DISABLED_event_only= 65 \n" ); document.write( "e)dramas or comedies? \n" ); document.write( "This would be A only + B only + AB only + AC only + BC only + ABC = 121 + 83 + 38 + 16 + 11 + 21 = 290. \n" ); document.write( "It includes A only because they like drama. \n" ); document.write( "It include B only because they like comedy. \n" ); document.write( "It includes AB only because they like drama and comedy. \n" ); document.write( "It includes AC only because they like drama. \n" ); document.write( "It include BC only because they like comedy \n" ); document.write( "It includes ABC only because they like drama and comedy. \n" ); document.write( "The only category it does not include is C only. Those customers only like Science. \n" ); document.write( " \n" ); document.write( " |