document.write( "Question 468394: Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers \n" ); document.write( "

Algebra.Com's Answer #321390 by jorel1380(3719) $\"\"$ $\"About$

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3(n)+1=(n+2)+(n+4)
\n" ); document.write( "3n+1=2n+6
\n" ); document.write( "n=5
\n" ); document.write( "n+2=7
\n" ); document.write( "n+4=9
\n" ); document.write( "The numbers are 5, 7, and 9.. \n" ); document.write( "

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