document.write( "Question 468361: I am trying to figure out how to solve this problem using the substitution method. I know that it equals 1000, but I can't figure out how to show the proper work. Any help of guidance would be appreciated. Thank you.\r
\n" ); document.write( "\n" ); document.write( "60+.20(x-550)=120+.15(x-800) \n" ); document.write( "

Algebra.Com's Answer #321378 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi
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document.write( "solving by:
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document.write( "60 + .20(x-550)=120 +.15(x-800)
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document.write( "1) removing the parenthesis
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document.write( "60+.20x-110 =120+.15x-120
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document.write( "2)combining Like terms
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document.write( " .20x - 50 = .15x               
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document.write( "3) Isolating the variable on one side of the EQ
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document.write( "     .05x = 50
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document.write( "        x = 50/.05
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document.write( "        x = 1000 \n" );
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