document.write( "Question 468244: A Math test has a mean of 39 and standard deviation of 10.0. Find the corresponding z scores for:
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document.write( "I. a test score of 82
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document.write( "II. A test score of 33 \n" );
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Algebra.Com's Answer #321368 by moshiz08(60)![]() ![]() You can put this solution on YOUR website! To find the z score, you subtract the mean and then divide by the standard deviation. In your example, the z score for a test score of 82 is (82-39)/10 = 4.3. The z score for a test score of 33 is (33-39)/10 = -0.6 \n" ); document.write( " |