document.write( "Question 468334: (log x)^3=log x^3 Please help I am not coming up with the right answer! \n" ); document.write( "
Algebra.Com's Answer #321336 by ccs2011(207)\"\" \"About 
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\"%28log+x%29%5E3+=+log+x%5E3\"
\n" ); document.write( "Use log property
\n" ); document.write( "\"log+x%5En+=+n%2Alog+x\"
\n" ); document.write( "\"%28log+x%29%5E3+=+3%2Alog+x\"
\n" ); document.write( "Divide by (log x) on both sides
\n" ); document.write( "\"%28log+x%29%5E2+=+3\"
\n" ); document.write( "Take square root of both sides
\n" ); document.write( "\"log+x+=+sqrt%283%29\"
\n" ); document.write( "**Assuming this is log base 10**
\n" ); document.write( "Rewrite in exponential form
\n" ); document.write( "\"x+=+10%5Esqrt%283%29\"
\n" ); document.write( "This yields 2 solutions (there should be plus-minus in front of radical):
\n" ); document.write( "x = 53.957 and x = 0.0185
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