document.write( "Question 468328: the sum of three consecutive integers is 25 larger than twice the smallest integer. find the integers. \n" ); document.write( "
Algebra.Com's Answer #321333 by algebrahouse.com(1659)\"\" \"About 
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\"the sum of three consecutive integers is 25 larger than twice the smallest integer. find the integers.\"\r
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\n" ); document.write( "\n" ); document.write( "x = 1st consecutive integer
\n" ); document.write( "x + 1 = 2nd consecutive integer
\n" ); document.write( "x + 2 = 3rd consecutive integer\r
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\n" ); document.write( "\n" ); document.write( "x + x + 1 + x + 2 = 2x + 25 {sum of the three is 25 larger than twice the smallest}
\n" ); document.write( "3x + 3 = 2x + 25 {combined like terms}
\n" ); document.write( "x + 3 = 25 {subtracted 2x from both sides}
\n" ); document.write( "x = 22 {subtracted 3 from both sides}
\n" ); document.write( "x + 1 = 23 {substituted 22, in for x, into x + 1}
\n" ); document.write( "x + 2 = 24 {substituted 22, in for x, into x + 2}\r
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\n" ); document.write( "\n" ); document.write( "22, 23, and 24 are the three consecutive integers
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