document.write( "Question 468317: Does y=11(8/13)^x represents exponential growth or exponential decay. \n" ); document.write( "
Algebra.Com's Answer #321332 by ccs2011(207)\"\" \"About 
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Given the exponential function:
\n" ); document.write( "\"y+=+a%2Ab%5Ex\"
\n" ); document.write( "where a is a constant scale factor and b is the base raised to power of x.
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\n" ); document.write( "If b > 1, then as x increases so does y, thus its a growth function.
\n" ); document.write( "Ex:
\n" ); document.write( "a=1, b=2
\n" ); document.write( "\"y+=+2%5Ex\"
\n" ); document.write( "If x = 1, y = 2^1 = 2
\n" ); document.write( "If x = 3, y = 2^3 = 8
\n" ); document.write( "...
\n" ); document.write( "\"graph%28200%2C200%2C-1%2C5%2C-1%2C20%2C2%5Ex%29\"
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\n" ); document.write( "If b < 1, then as x increases y decreases, thus its a decay function.
\n" ); document.write( "Ex:
\n" ); document.write( "a=1, b=1/2
\n" ); document.write( "\"y+=+%281%2F2%29%5Ex\"
\n" ); document.write( "If x = 1, y = (1/2)^1 = 1/2
\n" ); document.write( "If x = 3, y = (1/2)^3 = 1/8
\n" ); document.write( "...
\n" ); document.write( "\"graph%28200%2C200%2C-1%2C5%2C-1%2C2%2C0.5%5Ex%29\"
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\n" ); document.write( "Remember:
\n" ); document.write( "b > 1 ---> Growth
\n" ); document.write( "b < 1 ---> Decay
\n" ); document.write( "You can always check by plugging in x_values as well, I suggest 0 and 1.
\n" ); document.write( "If the y_value went up then its growth, if not its decay.
\n" ); document.write( "Lets look at your problem \"y+=+11%288%2F13%29%5Ex\"
\n" ); document.write( "a= 11, b = 8/13
\n" ); document.write( "8/13 < 1 --> Decay
\n" ); document.write( "\"y+=+11%288%2F13%29%5E0+=+11\"
\n" ); document.write( "\"y+=+11%288%2F13%29%5E1+=+88%2F13+=+6.77\"
\n" ); document.write( "y decreased therefore we confirm the function is a decay function.
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