document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468314>Question 468314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the area of a sector with a central angle of 270 and the radius of 11.5m round to the nearest </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321323 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the area of a sector we use the formula:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%28pi%2Ar%5E2%2Atheta%29%2F360 ALIGN=MIDDLE  ALT=\"A=%28pi%2Ar%5E2%2Atheta%29%2F360\"   DISABLED_style= \"max-width:90%; height:auto;\" >, where \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta=270 ALIGN=MIDDLE  ALT=\"theta=270\"   DISABLED_style= \"max-width:90%; height:auto;\" > degree is the central angle. Substituting we get:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%28pi%2A%2811.5%29%5E2%2A270%29%2F360 ALIGN=MIDDLE  ALT=\"A=%28pi%2A%2811.5%29%5E2%2A270%29%2F360\"   DISABLED_style= \"max-width:90%; height:auto;\" >, the area is about A=312 square meters. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );