document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468307>Question 468307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve by the substitution method.<BR>\n" );
document.write( "8x+7y=9<BR>\n" );
document.write( "-3x+y=22 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321319 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the second equation isolate y: y=3x+22. Substitute this value for y in the first equation:8x+7(3x+22)=9, solving this linear equation we get:29x=-145, and<BR>\n" );
document.write( "final x=-145/29. Plugging x=-145/29 in the equation y=3x+22 we get: y=3(-145/29)+22,<BR>\n" );
document.write( "and final y=7.<BR>\n" );
document.write( "Answer: the solution of our system is the ordered pair (-145/29, 7). </SPAN>\n" );
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