document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468275>Question 468275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Best Electronics, Inc. offers a “no hassle” returns policy. The number of items returned<BR>\n" );
document.write( "per day follows the normal distribution. The mean number of customer returns is 10.3<BR>\n" );
document.write( "per day and the standard deviation is 2.25 per day.<BR>\n" );
document.write( "a. In what percent of the days are there 8 or fewer customers returning items?<BR>\n" );
document.write( "b. In what percent of the days are between 12 and 14 customers returning items?<BR>\n" );
document.write( "c. Is there any chance of a day with no returns?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321286 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Best Electronics, Inc. offers a “no hassle” returns policy. The number of items returned per day follows the normal distribution. <BR>\n" );
document.write( "The mean number of customer returns is 10.3<BR>\n" );
document.write( "per day and the standard deviation is 2.25 per day.<BR>\n" );
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document.write( "a. In what percent of the days are there 8 or fewer customers returning items?<BR>\n" );
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document.write( "z(8) = (8-10.3)/2.25 = -1.0222<BR>\n" );
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document.write( "%(x <= 8) = %(z <= -1.0222) = 15.33%<BR>\n" );
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document.write( "b. In what percent of the days are between 12 and 14 customers returning items?<BR>\n" );
document.write( "Normalcdf(12,14,10.3,2.25) = 17.49%<BR>\n" );
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document.write( "c. Is there any chance of a day with no returns?<BR>\n" );
document.write( "z(0) = (0-10.3)/2.25 = -4.5778<BR>\n" );
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document.write( "%(x <= 0) = %(z <--4.5778) = 0.00023518%<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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