document.write( "Question 468234: Meg rowed her boat upstream a distance of 5 miles and then rowed back to the starting point. The total time of the trip was 6 hours. If the rate of the current was 2 mph, find the average speed of the boat relative to the water. \n" ); document.write( "
Algebra.Com's Answer #321276 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Boat speed x \n" ); document.write( "current speed 2 \n" ); document.write( " \n" ); document.write( "against current x-2 mph \n" ); document.write( "with current x+ 2 mph \n" ); document.write( " \n" ); document.write( "Distance= 5 miles \n" ); document.write( " \n" ); document.write( "Time against + time with = 6 hours\r \n" ); document.write( "\n" ); document.write( "5 /( x + 2 ) + 5 /(x - 2 ) = 6 \n" ); document.write( " \n" ); document.write( "LCD = (x - 2 ) ( x + 2 ) \n" ); document.write( "5 *( x - 2 ) + 5 (x + 2 ) = 6 \n" ); document.write( "5 x - 10 + 5 x + 10 = 6 ( x ^2 - 4 ) \n" ); document.write( "10 x = 6 x ^2 - 24 \n" ); document.write( "6 x ^2 - -10 x - 24 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( "a= 6 , b= -10 , c= -24 \n" ); document.write( "b^2-4ac= 100 + 576 \n" ); document.write( "b^2-4ac=676 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=(10+26)/12 \n" ); document.write( "x1=3 \n" ); document.write( "x2=(10-26)/12 \n" ); document.write( "x2= -1.33 \n" ); document.write( "Ignore negative value \n" ); document.write( "Speed of boat is 3 mph \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |