document.write( "Question 468234: Meg rowed her boat upstream a distance of 5 miles and then rowed back to the starting point. The total time of the trip was 6 hours. If the rate of the current was 2 mph, find the average speed of the boat relative to the water. \n" ); document.write( "
Algebra.Com's Answer #321276 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Boat speed x
\n" ); document.write( "current speed 2
\n" ); document.write( "
\n" ); document.write( "against current x-2 mph
\n" ); document.write( "with current x+ 2 mph
\n" ); document.write( "
\n" ); document.write( "Distance= 5 miles
\n" ); document.write( "
\n" ); document.write( "Time against + time with = 6 hours\r
\n" ); document.write( "\n" ); document.write( "5 /( x + 2 ) + 5 /(x - 2 ) = 6
\n" ); document.write( "
\n" ); document.write( "LCD = (x - 2 ) ( x + 2 )
\n" ); document.write( "5 *( x - 2 ) + 5 (x + 2 ) = 6
\n" ); document.write( "5 x - 10 + 5 x + 10 = 6 ( x ^2 - 4 )
\n" ); document.write( "10 x = 6 x ^2 - 24
\n" ); document.write( "6 x ^2 - -10 x - 24
\n" ); document.write( "
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "a= 6 , b= -10 , c= -24
\n" ); document.write( "b^2-4ac= 100 + 576
\n" ); document.write( "b^2-4ac=676
\n" ); document.write( "\"%09sqrt%28%09676%09%29=%0926%09\"
\n" ); document.write( "\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"
\n" ); document.write( "x1=(10+26)/12
\n" ); document.write( "x1=3
\n" ); document.write( "x2=(10-26)/12
\n" ); document.write( "x2= -1.33
\n" ); document.write( "Ignore negative value
\n" ); document.write( "Speed of boat is 3 mph \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );