document.write( "Question 468084: A lab designed radio telescope with diaeter of 320 ft & maximum depth of 42 ft Find the equation of the parabola and graph. \n" ); document.write( "
Algebra.Com's Answer #321275 by lwsshak3(11628)\"\" \"About 
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A lab designed radio telescope with diameter of 320 ft & maximum depth of 42 ft Find the equation of the parabola and graph.
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\n" ); document.write( "Standard form for a parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "Given radio telescope is a parabola that opens upwards.
\n" ); document.write( "Draw a diagram with the left side of the parabola at the origin, (0,0) and the right side at (320,0) Coordinates of the vertex are at (160,-42). This also gives the parabola an axis of symmetry at x=160.
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\n" ); document.write( "y=A(x-h)^2+k
\n" ); document.write( "using (x,y) coordinates of one point (0,0) on the curve and (x,y) coordinates of the vertex:
\n" ); document.write( "0=A(0-160)^2-42
\n" ); document.write( "A=42/(-160)^2=42/25600=.0016
\n" ); document.write( "Equation of parabola:
\n" ); document.write( "y=.0016(x-160)^2-42
\n" ); document.write( "See graph below:
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+400%2C+400%2C+-20%2C+400%2C+-400%2C+20%2C.0016%28x-160%29%5E2-42%29+\"
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