document.write( "Question 468208: I need a little help here:\r
\n" ); document.write( "\n" ); document.write( "ln(x+9)-ln(x-5)=ln(x+7)-ln(x-4).\r
\n" ); document.write( "\n" ); document.write( "Apparently there is no solution? Why not x=1/3?!
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Algebra.Com's Answer #321255 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
ln(x+9)-ln(x-5)=ln(x+7)-ln(x-4).\r
\n" ); document.write( "\n" ); document.write( "Apparently there is no solution? Why not x=1/3?!
\n" ); document.write( "------------------
\n" ); document.write( "\"ln%28%28x%2B9%29%2F%28x%2B5%29%29+=+ln%28%28x%2B7%29%2F%28x-4%29%29\"
\n" ); document.write( "\"%28x%2B9%29%2F%28x-5%29+=+%28x%2B7%29%2F%28x-4%29\"
\n" ); document.write( "\"x%2B9%29%2A%28x-4%29+=+%28x-5%29%2A%28x%2B7%29\"
\n" ); document.write( "\"x%5E2+%2B+5x+-+36+=+x%5E2+%2B+2x+-+35\"
\n" ); document.write( "3x = 1
\n" ); document.write( "x = 1/3
\n" ); document.write( "----------------
\n" ); document.write( "x = 1/3 makes ln(x-5) and ln(x-4) the logs of negative numbers.
\n" ); document.write( " --> no solution.
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