document.write( "Question 468154: Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol? \n" ); document.write( "
Algebra.Com's Answer #321221 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol? \n" ); document.write( "------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "--- \n" ); document.write( "0.10x + 0.90(80-x) = 0.35*80 \n" ); document.write( "----- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "10x + 90*80 - 90x = 35*80 \n" ); document.write( "-70x = -55*80 \n" ); document.write( "x = (8/7)*55 \n" ); document.write( "x = 62.86 quarts (amt. of 10% solution needed) \n" ); document.write( "--- \n" ); document.write( "80-x = 80-62.86 = 17.14 quarts (amt. of 90% solution needed) \n" ); document.write( "================================================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |