document.write( "Question 468154: Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol? \n" ); document.write( "
Algebra.Com's Answer #321221 by stanbon(75887)\"\" \"About 
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Suppose that you have a supply of a 10% solution of alcohol and a 90% solution of alcohol. How many quarts of each should be mixed to produce 80 quarts that is 35% alcohol?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol + alcohol = alcohol
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\n" ); document.write( "0.10x + 0.90(80-x) = 0.35*80
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "10x + 90*80 - 90x = 35*80
\n" ); document.write( "-70x = -55*80
\n" ); document.write( "x = (8/7)*55
\n" ); document.write( "x = 62.86 quarts (amt. of 10% solution needed)
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\n" ); document.write( "80-x = 80-62.86 = 17.14 quarts (amt. of 90% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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