document.write( "Question 467998: what is the directx of 8x=y^2 \n" ); document.write( "
Algebra.Com's Answer #321151 by lwsshak3(11628)\"\" \"About 
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what is the directrix of 8x=y^2
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\n" ); document.write( "Standard form for given parabola; (y-k)^2=4p(x-h), with (h,k) being the (x,y) coordinates of the vertex.
\n" ); document.write( "For given parabola: y^2=8x
\n" ); document.write( "vertex is at origin (0,0), parabola opens rightwards
\n" ); document.write( "4p=8
\n" ); document.write( "p=4
\n" ); document.write( "Directrix is a vertical line 4 units from the vertex at x=-4
\n" ); document.write( "see graph below as a visual check on answer
\n" ); document.write( "..
\n" ); document.write( "y=±(8x)^.5
\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C%288x%29%5E.5%2C-%288x%29%5E.5%29+\" \n" ); document.write( "
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