document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=468048>Question 468048</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I solve:\r<BR>\n" );
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document.write( "-19<3x-17<34\r<BR>\n" );
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document.write( "***The second less than is a less than or equal to. I couldn't do that on a keyboard.<BR>\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321128 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321128\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I solve: <BR>\n" );
document.write( "-19 < 3x-17 <= 34 <BR>\n" );
document.write( "Add 17<BR>\n" );
document.write( "-2 < 3x <= 51<BR>\n" );
document.write( "Divide by 3<BR>\n" );
document.write( "-2/3 < x <= 17<BR>\n" );
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