document.write( "Question 468002: solve\r
\n" ); document.write( "\n" ); document.write( "Vy+5 -1=3\r
\n" ); document.write( "\n" ); document.write( "the v is suppose to represent a square root (ex:the square root of y+5)
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Algebra.Com's Answer #321112 by nyc_function(2741)\"\" \"About 
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sqrt{y+5} -1 = 3\r
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\n" ); document.write( "\n" ); document.write( "Isolate the radical as step one.\r
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\n" ); document.write( "\n" ); document.write( "sqrt{y + 5} = 3 + 1\r
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\n" ); document.write( "\n" ); document.write( "sqrt{y + 5} = 4\r
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\n" ); document.write( "\n" ); document.write( "We now square both sides of the equation. We must square in order to remove the radical from the equation.\r
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\n" ); document.write( "\n" ); document.write( "[sqrt{y + 5}]^2 = (4)^2\r
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\n" ); document.write( "\n" ); document.write( "y + 5 = 16\r
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\n" ); document.write( "\n" ); document.write( "y = 16 - 5\r
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\n" ); document.write( "\n" ); document.write( "y = 11\r
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\n" ); document.write( "\n" ); document.write( "We now plug y = 11 into the given question.\r
\n" ); document.write( "\n" ); document.write( "The goal is to get the same answer on both sides of the equation.\r
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\n" ); document.write( "\n" ); document.write( "sqrt{y+5} -1 = 3\r
\n" ); document.write( "\n" ); document.write( "Let y = 11\r
\n" ); document.write( "\n" ); document.write( "sqrt{11+5} -1 = 3\r
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\n" ); document.write( "\n" ); document.write( "sqrt{16} - 1 = 3\r
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\n" ); document.write( "\n" ); document.write( "4 - 1 = 3\r
\n" ); document.write( "\n" ); document.write( "3 = 3...It checks!!\r
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\n" ); document.write( "\n" ); document.write( "The right answer is y = 11.\r
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\n" ); document.write( "\n" ); document.write( "Done!\r
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