document.write( "Question 468017: what is the perimeter of a right triangle with its legs measuring 7 and 24 \n" ); document.write( "
Algebra.Com's Answer #321103 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"what is the perimeter of a right triangle with its legs measuring 7 and 24\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Pythagorean Theorem \n" ); document.write( "a² + b² = c² {a and b are the legs and c is the hypotenuse} \n" ); document.write( "7² + 24² = c² {substituted into Pythagorean Theorem} \n" ); document.write( "49 + 576 = c² {squared 7 and 24} \n" ); document.write( "625 = c² {combined like terms} \n" ); document.write( "c = 25 {evaluated square root of 625 to be 25}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter of a triangle = all sides added together\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perimeter = 7 + 24 + 25 \n" ); document.write( "= 56 \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |