document.write( "Question 467742: Suppose that the width of a certain rectangle is 5 inches more than one-fourth of its length. The perimeter of the rectangle is 80 inches. Find the length and width of the rectangle \n" ); document.write( "

Algebra.Com's Answer #321085 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "width of a certain rectangle is 5 inches more than one-fourth of its length
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document.write( "Let x and (.25x + 5in) represent the length and width respectively
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document.write( "Question states***
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document.write( " 2(x)  +  2*(.25x+5in) = 80in
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document.write( "Solving for x
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document.write( "     2.5x = 70in
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document.write( "      x = 28in, the length.  the width is 12in   (.25*28in + 5)\r
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document.write( "CHECKING our Answer***
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document.write( "  2*28in + 2*12in = 80in \n" );
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