document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467909>Question 467909</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 2 numbers is 45,2/3 of the smaller number is greater than 1/5 of the larger number by 4. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321071 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the smaller number<BR>\n" );
document.write( "Then 45-x=the larger number<BR>\n" );
document.write( "Now we are told that:<BR>\n" );
document.write( "(2/3)x=(1/5)(45-x)+4 multiply each term by 15<BR>\n" );
document.write( "10x=3(45-x)+60 get rid of parens<BR>\n" );
document.write( "10x=135-3x+60 add 3x to each side<BR>\n" );
document.write( "10x+3x=135-3x+3x+60  collect like terms<BR>\n" );
document.write( "13x=195<BR>\n" );
document.write( "x=15------------------smaller number<BR>\n" );
document.write( "45-x=45-15=30 larger number<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(2/3)*15=(1/5)*30+4<BR>\n" );
document.write( "10=10\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );