document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467816>Question 467816</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If y = 1/(x+1), then what is x in terms of y? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321020 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321020\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1<BR>\n" );
document.write( "----- = y , solve for x<BR>\n" );
document.write( "x + 1\r<BR>\n" );
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document.write( "1 = y(x + 1) {multiplied both sides by x + 1}\r<BR>\n" );
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document.write( "1<BR>\n" );
document.write( "-- = x + 1 {divided both sides by y}<BR>\n" );
document.write( "y\r<BR>\n" );
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document.write( "1<BR>\n" );
document.write( "-- - 1 = x {subtracted 1 from both sides}<BR>\n" );
document.write( "y\r<BR>\n" );
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document.write( "1 - y<BR>\n" );
document.write( "------ = x {got common denominator and combined the terms on left side}<BR>\n" );
document.write( "y<BR>\n" );
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