document.write( "Question 466723: The width of rectangle is 5ft less than the length. the area is 6ft^2, what is width and length? \n" ); document.write( "
Algebra.Com's Answer #321015 by gwendolyn(128)\"\" \"About 
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We have two variables in this equation, width and length. We'll say that L=length and W=width.
\n" ); document.write( "The first piece of information we have is that the width is equal to the length minus 5 feet. This can be turned into an equation:
\n" ); document.write( "W=L-5
\n" ); document.write( "The other information we are provided is that the rectangle's area, which is equal to length times width, is 6 square feet. This too can be made into an equation:
\n" ); document.write( "L*W=6
\n" ); document.write( "We can plug the first equation into the second, since we have the variable 'W' isolated already.
\n" ); document.write( "L*(L-5)=6
\n" ); document.write( "Then, we can distribute the L.
\n" ); document.write( "\"L%5E2-5L=6\"
\n" ); document.write( "Subtract 6 from both sides.
\n" ); document.write( "\"L%5E2-5L-6=0\"
\n" ); document.write( "We can now factor this quadratic equation.
\n" ); document.write( "(L-6)(L+1)=0
\n" ); document.write( "This means that L is equal to either 6 or -1. Since L is a length, it has to be the positive option, so L=6.
\n" ); document.write( "We can now plug this value into the first equation to find the width.
\n" ); document.write( "6-5=W
\n" ); document.write( "1=W
\n" ); document.write( "Therefore, the width is 1 and the length is 6.
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