document.write( "Question 466723: The width of rectangle is 5ft less than the length. the area is 6ft^2, what is width and length? \n" ); document.write( "
Algebra.Com's Answer #321015 by gwendolyn(128)![]() ![]() You can put this solution on YOUR website! We have two variables in this equation, width and length. We'll say that L=length and W=width. \n" ); document.write( "The first piece of information we have is that the width is equal to the length minus 5 feet. This can be turned into an equation: \n" ); document.write( "W=L-5 \n" ); document.write( "The other information we are provided is that the rectangle's area, which is equal to length times width, is 6 square feet. This too can be made into an equation: \n" ); document.write( "L*W=6 \n" ); document.write( "We can plug the first equation into the second, since we have the variable 'W' isolated already. \n" ); document.write( "L*(L-5)=6 \n" ); document.write( "Then, we can distribute the L. \n" ); document.write( " \n" ); document.write( "Subtract 6 from both sides. \n" ); document.write( " \n" ); document.write( "We can now factor this quadratic equation. \n" ); document.write( "(L-6)(L+1)=0 \n" ); document.write( "This means that L is equal to either 6 or -1. Since L is a length, it has to be the positive option, so L=6. \n" ); document.write( "We can now plug this value into the first equation to find the width. \n" ); document.write( "6-5=W \n" ); document.write( "1=W \n" ); document.write( "Therefore, the width is 1 and the length is 6. \n" ); document.write( " |