document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48097>Question 48097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if f(x)=x(x+1)(x-4), use iterval notation to give all values of x where f(x)>0\r<BR>\n" );
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document.write( "i come up with (-1,4) am i missing something ? thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32101 by </B><A HREF=/tutors/aboutme.mpl?userid=cowess><B>cowess(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cowess><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32101\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=x(x+1)(x-4), <BR>\n" );
document.write( "your answer is incorrect because when x= 0 or -1 or 4, f(0)=f(-1)=f(4)=0<BR>\n" );
document.write( "for the trigonomial f(x)to be positive(>0)<BR>\n" );
document.write( "the three factors in this trigonomial x,(x+1),(x-4) should be<BR>\n" );
document.write( "1)all three are positive, their product is positive.<BR>\n" );
document.write( "2)two are negative and one positive, their product is also positive.\r<BR>\n" );
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document.write( "ANS:  x>4     (x,(x+1),(x-4) all >0)<BR>\n" );
document.write( "   or -1<x<0  ((x+1)>0 and x,(x-4)<0) </SPAN>\n" );
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