document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467740>Question 467740</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I am in need of help with a problem. The directions are, use a algebraic equation to find the measures of the two angles discribed. Begin by letting x represent the degree measure of the angle's complement or its supplement.\r<BR>\n" );
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document.write( "The measure of the angle is 81degrees more than twice that of its supplement.\r<BR>\n" );
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document.write( "I would really appreciate it if someone could help me. Thank you in advance  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320954 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320954\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+2x+81=180<BR>\n" );
document.write( "3x=99<BR>\n" );
document.write( "x=33<BR>\n" );
document.write( "2x+81=147 </SPAN>\n" );
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