document.write( "Question 467644: find the sin(a+b) if tan(a) = 7/24 where a is in the third quadrant and cos (b)= -12/13 where b is in the second quadrant \n" ); document.write( "
Algebra.Com's Answer #320941 by lwsshak3(11628)\"\" \"About 
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Find the sin(a+b) if tan(a) = 7/24 where a is in the third quadrant and cos (b)= -12/13 where b is in the second quadrant
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\n" ); document.write( "Identity required: sin(a+b)=sin a cos b +cos a sin b
\n" ); document.write( "so we must find sin a, sin b, cos a and cos b
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\n" ); document.write( "Given: tan (a) =7/24 in quadrant III
\n" ); document.write( "This gives a hypotenuse=√(24^2+7^2)=√625=25
\n" ); document.write( "In quadrant III, both sin and cos are <0
\n" ); document.write( "sin a=-7/25
\n" ); document.write( "cos a=-24/25
\n" ); document.write( "..
\n" ); document.write( "Given: cos (b)=-12/13 in quadrant II (cos<0, sin>0)
\n" ); document.write( "Opposite leg=√(13^2-12^2)=√25=5
\n" ); document.write( "Sin b=5/13
\n" ); document.write( "..
\n" ); document.write( "sin(a+b)=(-7/25)(-12/13)+(-24/25)(5/13)
\n" ); document.write( "=.2585-.3692=.1107
\n" ); document.write( "..
\n" ); document.write( "ans: sin(a+b)=.1107
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