document.write( "Question 467693: a rectangle is twicw as long as it is wide. the perimeter is 60 feet. find the dimension \n" ); document.write( "

Algebra.Com's Answer #320922 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "rectangle is twice as long as it is wide
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document.write( "Let x and 2x represent the width and length respectively
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document.write( "Note:  P(rectangle) = 2*L + 2*W
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document.write( " P = 2x + 2*(2x) = 60ft
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document.write( "          6x = 60ft
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document.write( "           x = 10ft, the width.  The length is 20ft (2*10ft)
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