document.write( "Question 467503: Joan's present weight is 17 pounds less than her weight 2 years ago. If her weight at that time was 8/7 of her present weight, what is her present weight in pounds?\r
\n" ); document.write( "\n" ); document.write( "A) 60
\n" ); document.write( "B) 68
\n" ); document.write( "C) 119
\n" ); document.write( "D) 136
\n" ); document.write( "E) 272\r
\n" ); document.write( "\n" ); document.write( "I plugged in all the choices (which I know isn't a valid/good method) into this equation I came up with from the information given: (8/7)(X)= X + 17
\n" ); document.write( "The answer that worked was C) 119. But I'd like to know how to solve the problem without having to plug in all the numbers.\r
\n" ); document.write( "\n" ); document.write( "Thank you!
\n" ); document.write( "

Algebra.Com's Answer #320780 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let Joan be x lb 2 years ago
\n" ); document.write( "Present weight = x-17 lb\r
\n" ); document.write( "\n" ); document.write( "8/7(x-17) = x
\n" ); document.write( "multiply by 7
\n" ); document.write( "8x-136=7x
\n" ); document.write( "8x-7x=136
\n" ); document.write( "x=136\r
\n" ); document.write( "\n" ); document.write( "Two years ago she was 136 lb
\n" ); document.write( "now she is 136-17 = 119 lb
\n" ); document.write( "
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