document.write( "Question 467444: How many gallons of a 60% antifreeze solution must be mixed with 70 gallons of 25% antifreeze to get a mixture that is 50% antifreeze? Use 6 step method. \n" ); document.write( "
Algebra.Com's Answer #320779 by mananth(16946)![]() ![]() You can put this solution on YOUR website! ----------- percent ---------------- quantity \n" ); document.write( "Antifreeeze I 25 ---------------- 70 L \n" ); document.write( "Antifreeze II 60 ---------------- x L \n" ); document.write( "Total 50 ---------------- 70 + x L \n" ); document.write( " \n" ); document.write( "25*70+60*x=50(70+x) \n" ); document.write( " \n" ); document.write( "1750+60x=3500+50x \n" ); document.write( " \n" ); document.write( "60x-50x=3500-1750 \n" ); document.write( " \n" ); document.write( "10x=1750 \n" ); document.write( " \n" ); document.write( "/10 \n" ); document.write( " \n" ); document.write( "x=175 L 60 % Antifreeze II \n" ); document.write( " \n" ); document.write( " |