document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=467363>Question 467363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me with this tough question?\r<BR>\n" );
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document.write( "\"An open box is to be constructed from 84 square inches of material. What should be the dimensions of the base if the height of the box is to be 2 inches? Surface Area: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=S=+x%5E2+%2B+4xh+ ALIGN=MIDDLE  ALT=\"S=+x%5E2+%2B+4xh+\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #320723 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=320723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"An open box is to be constructed from 84 square inches of material.<BR>\n" );
document.write( " What should be the dimensions of the base if the height of the box is to be 2 inches? <BR>\n" );
document.write( "Surface Area: S = x^2 + 4xh<BR>\n" );
document.write( "height is given as 2\", therefore<BR>\n" );
document.write( "SA = x^2 + 4x*2<BR>\n" );
document.write( "SA = x^2 + 8x<BR>\n" );
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document.write( "The base is square, therefore the material is square<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2884%29 ALIGN=MIDDLE  ALT=\"sqrt%2884%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 9.165\" square<BR>\n" );
document.write( "x =  9.165 - 2(2); subtract the 2\" used for the 2\" height on each side<BR>\n" );
document.write( "x = 9.165 - 4<BR>\n" );
document.write( "x = 5.165\" length and width of the base<BR>\n" );
document.write( "Surface area<BR>\n" );
document.write( "SA = 5.165^2 + 8(5.165)<BR>\n" );
document.write( "SA = 26.677 + 41.32<BR>\n" );
document.write( "SA = 68 sq/inches, surface area of the box<BR>\n" );
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document.write( "We can check this, 4 each 2\" squares removed to accomplish this<BR>\n" );
document.write( "Total area of these squares: 4(4) = 16 <BR>\n" );
document.write( "Box area plus 2\" square areas should = the original material area<BR>\n" );
document.write( "68 + 16 = 84<BR>\n" );
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document.write( "It just dawned me we could have done this in our head. Given the height is 2\" we know that 4 ea 2\" squares will be removed for a total of 16 square inches.<BR>\n" );
document.write( "What remains, is the surface area of the box, 84-16 = 68 sq/inches!<BR>\n" );
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