document.write( "Question 467419: If 4 is added to a number and the sum is tripled the results 16 more than the number. find the number \n" ); document.write( "
Algebra.Com's Answer #320721 by jim_thompson5910(35256)\"\" \"About 
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\"If 4 is added to a number and the sum is tripled the results 16 more than the number\" means that \"3%28x%2B4%29=x%2B16\"\r
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\n" ); document.write( "\n" ); document.write( "\"3%28x%2B4%29=x%2B16\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%2B12=x%2B16\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=x%2B16-12\" Subtract \"12\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-x=16-12\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=16-12\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=4\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%284%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=2\"
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